Optimal. Leaf size=141 \[ -\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}+\frac {2 i a^2 (c+d \tan (e+f x))^3}{3 f}+\frac {a^2 (d+i c) (c+d \tan (e+f x))^2}{f}+\frac {2 i a^2 d (c-i d)^2 \tan (e+f x)}{f}+\frac {2 a^2 (d+i c)^3 \log (\cos (e+f x))}{f}+2 a^2 x (c-i d)^3 \]
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Rubi [A] time = 0.20, antiderivative size = 141, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3543, 3528, 3525, 3475} \[ -\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}+\frac {2 i a^2 (c+d \tan (e+f x))^3}{3 f}+\frac {a^2 (d+i c) (c+d \tan (e+f x))^2}{f}+\frac {2 i a^2 d (c-i d)^2 \tan (e+f x)}{f}+\frac {2 a^2 (d+i c)^3 \log (\cos (e+f x))}{f}+2 a^2 x (c-i d)^3 \]
Antiderivative was successfully verified.
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Rule 3475
Rule 3525
Rule 3528
Rule 3543
Rubi steps
\begin {align*} \int (a+i a \tan (e+f x))^2 (c+d \tan (e+f x))^3 \, dx &=-\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}+\int \left (2 a^2+2 i a^2 \tan (e+f x)\right ) (c+d \tan (e+f x))^3 \, dx\\ &=\frac {2 i a^2 (c+d \tan (e+f x))^3}{3 f}-\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}+\int (c+d \tan (e+f x))^2 \left (2 a^2 (c-i d)+2 a^2 (i c+d) \tan (e+f x)\right ) \, dx\\ &=\frac {a^2 (i c+d) (c+d \tan (e+f x))^2}{f}+\frac {2 i a^2 (c+d \tan (e+f x))^3}{3 f}-\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}+\int \left (2 a^2 (c-i d)^2+2 i a^2 (c-i d)^2 \tan (e+f x)\right ) (c+d \tan (e+f x)) \, dx\\ &=2 a^2 (c-i d)^3 x+\frac {2 i a^2 (c-i d)^2 d \tan (e+f x)}{f}+\frac {a^2 (i c+d) (c+d \tan (e+f x))^2}{f}+\frac {2 i a^2 (c+d \tan (e+f x))^3}{3 f}-\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}-\left (2 a^2 (i c+d)^3\right ) \int \tan (e+f x) \, dx\\ &=2 a^2 (c-i d)^3 x+\frac {2 a^2 (i c+d)^3 \log (\cos (e+f x))}{f}+\frac {2 i a^2 (c-i d)^2 d \tan (e+f x)}{f}+\frac {a^2 (i c+d) (c+d \tan (e+f x))^2}{f}+\frac {2 i a^2 (c+d \tan (e+f x))^3}{3 f}-\frac {a^2 (c+d \tan (e+f x))^4}{4 d f}\\ \end {align*}
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Mathematica [B] time = 8.60, size = 733, normalized size = 5.20 \[ \frac {\sec ^2(e+f x) (a+i a \tan (e+f x))^2 \left (\frac {1}{24} \sec (e) (\cos (2 e)-i \sin (2 e)) \left (-9 c^3 \sin (e+2 f x)+3 c^3 \sin (3 e+2 f x)-3 c^3 \sin (3 e+4 f x)+12 c^3 f x \cos (3 e+2 f x)+3 c^3 f x \cos (3 e+4 f x)+3 c^3 f x \cos (5 e+4 f x)+9 c^3 \sin (e)+54 i c^2 d \sin (e+2 f x)-18 i c^2 d \sin (3 e+2 f x)+18 i c^2 d \sin (3 e+4 f x)-9 c^2 d \cos (3 e+2 f x)-36 i c^2 d f x \cos (3 e+2 f x)-9 i c^2 d f x \cos (3 e+4 f x)-9 i c^2 d f x \cos (5 e+4 f x)-54 i c^2 d \sin (e)+6 \cos (e) \left (3 c^3 f x+c^2 d (-3-9 i f x)+3 c d^2 (-3 f x+2 i)+d^3 (2+3 i f x)\right )+57 c d^2 \sin (e+2 f x)-27 c d^2 \sin (3 e+2 f x)+21 c d^2 \sin (3 e+4 f x)+18 i c d^2 \cos (3 e+2 f x)-36 c d^2 f x \cos (3 e+2 f x)-9 c d^2 f x \cos (3 e+4 f x)-9 c d^2 f x \cos (5 e+4 f x)-63 c d^2 \sin (e)+3 (c-i d)^2 (4 c f x-4 i d f x-3 d) \cos (e+2 f x)-20 i d^3 \sin (e+2 f x)+12 i d^3 \sin (3 e+2 f x)-8 i d^3 \sin (3 e+4 f x)+9 d^3 \cos (3 e+2 f x)+12 i d^3 f x \cos (3 e+2 f x)+3 i d^3 f x \cos (3 e+4 f x)+3 i d^3 f x \cos (5 e+4 f x)+24 i d^3 \sin (e)\right )+2 f x (c-i d)^3 (\cos (2 e)-i \sin (2 e)) \cos ^4(e+f x)-2 (c-i d)^3 (\cos (2 e)-i \sin (2 e)) \cos ^4(e+f x) \tan ^{-1}(\tan (3 e+f x))+(c-i d)^3 (-\sin (2 e)-i \cos (2 e)) \cos ^4(e+f x) \log \left (\cos ^2(e+f x)\right )\right )}{f (\cos (f x)+i \sin (f x))^2} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.47, size = 451, normalized size = 3.20 \[ \frac {-6 i \, a^{2} c^{3} - 36 \, a^{2} c^{2} d + 42 i \, a^{2} c d^{2} + 16 \, a^{2} d^{3} + {\left (-6 i \, a^{2} c^{3} - 54 \, a^{2} c^{2} d + 90 i \, a^{2} c d^{2} + 42 \, a^{2} d^{3}\right )} e^{\left (6 i \, f x + 6 i \, e\right )} + {\left (-18 i \, a^{2} c^{3} - 144 \, a^{2} c^{2} d + 198 i \, a^{2} c d^{2} + 72 \, a^{2} d^{3}\right )} e^{\left (4 i \, f x + 4 i \, e\right )} + {\left (-18 i \, a^{2} c^{3} - 126 \, a^{2} c^{2} d + 150 i \, a^{2} c d^{2} + 58 \, a^{2} d^{3}\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + {\left (-6 i \, a^{2} c^{3} - 18 \, a^{2} c^{2} d + 18 i \, a^{2} c d^{2} + 6 \, a^{2} d^{3} + {\left (-6 i \, a^{2} c^{3} - 18 \, a^{2} c^{2} d + 18 i \, a^{2} c d^{2} + 6 \, a^{2} d^{3}\right )} e^{\left (8 i \, f x + 8 i \, e\right )} + {\left (-24 i \, a^{2} c^{3} - 72 \, a^{2} c^{2} d + 72 i \, a^{2} c d^{2} + 24 \, a^{2} d^{3}\right )} e^{\left (6 i \, f x + 6 i \, e\right )} + {\left (-36 i \, a^{2} c^{3} - 108 \, a^{2} c^{2} d + 108 i \, a^{2} c d^{2} + 36 \, a^{2} d^{3}\right )} e^{\left (4 i \, f x + 4 i \, e\right )} + {\left (-24 i \, a^{2} c^{3} - 72 \, a^{2} c^{2} d + 72 i \, a^{2} c d^{2} + 24 \, a^{2} d^{3}\right )} e^{\left (2 i \, f x + 2 i \, e\right )}\right )} \log \left (e^{\left (2 i \, f x + 2 i \, e\right )} + 1\right )}{3 \, {\left (f e^{\left (8 i \, f x + 8 i \, e\right )} + 4 \, f e^{\left (6 i \, f x + 6 i \, e\right )} + 6 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 4 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 2.58, size = 904, normalized size = 6.41 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 360, normalized size = 2.55 \[ \frac {3 i a^{2} \left (\tan ^{2}\left (f x +e \right )\right ) c \,d^{2}}{f}-\frac {a^{2} d^{3} \left (\tan ^{4}\left (f x +e \right )\right )}{4 f}+\frac {2 i a^{2} \arctan \left (\tan \left (f x +e \right )\right ) d^{3}}{f}-\frac {a^{2} \left (\tan ^{3}\left (f x +e \right )\right ) c \,d^{2}}{f}+\frac {2 i a^{2} \left (\tan ^{3}\left (f x +e \right )\right ) d^{3}}{3 f}+\frac {i a^{2} \ln \left (1+\tan ^{2}\left (f x +e \right )\right ) c^{3}}{f}-\frac {3 a^{2} \left (\tan ^{2}\left (f x +e \right )\right ) c^{2} d}{2 f}+\frac {a^{2} \left (\tan ^{2}\left (f x +e \right )\right ) d^{3}}{f}-\frac {a^{2} c^{3} \tan \left (f x +e \right )}{f}+\frac {6 a^{2} \tan \left (f x +e \right ) c \,d^{2}}{f}-\frac {2 i a^{2} d^{3} \tan \left (f x +e \right )}{f}+\frac {6 i a^{2} c^{2} d \tan \left (f x +e \right )}{f}+\frac {3 a^{2} \ln \left (1+\tan ^{2}\left (f x +e \right )\right ) c^{2} d}{f}-\frac {a^{2} \ln \left (1+\tan ^{2}\left (f x +e \right )\right ) d^{3}}{f}-\frac {3 i a^{2} \ln \left (1+\tan ^{2}\left (f x +e \right )\right ) c \,d^{2}}{f}-\frac {6 i a^{2} \arctan \left (\tan \left (f x +e \right )\right ) c^{2} d}{f}+\frac {2 a^{2} \arctan \left (\tan \left (f x +e \right )\right ) c^{3}}{f}-\frac {6 a^{2} \arctan \left (\tan \left (f x +e \right )\right ) c \,d^{2}}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.52, size = 217, normalized size = 1.54 \[ -\frac {3 \, a^{2} d^{3} \tan \left (f x + e\right )^{4} + {\left (12 \, a^{2} c d^{2} - 8 i \, a^{2} d^{3}\right )} \tan \left (f x + e\right )^{3} + {\left (18 \, a^{2} c^{2} d - 36 i \, a^{2} c d^{2} - 12 \, a^{2} d^{3}\right )} \tan \left (f x + e\right )^{2} - 12 \, {\left (2 \, a^{2} c^{3} - 6 i \, a^{2} c^{2} d - 6 \, a^{2} c d^{2} + 2 i \, a^{2} d^{3}\right )} {\left (f x + e\right )} - 12 \, {\left (i \, a^{2} c^{3} + 3 \, a^{2} c^{2} d - 3 i \, a^{2} c d^{2} - a^{2} d^{3}\right )} \log \left (\tan \left (f x + e\right )^{2} + 1\right ) + {\left (12 \, a^{2} c^{3} - 72 i \, a^{2} c^{2} d - 72 \, a^{2} c d^{2} + 24 i \, a^{2} d^{3}\right )} \tan \left (f x + e\right )}{12 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.06, size = 223, normalized size = 1.58 \[ \frac {{\mathrm {tan}\left (e+f\,x\right )}^2\,\left (\frac {a^2\,d^3}{2}+\frac {a^2\,d^2\,\left (d+c\,3{}\mathrm {i}\right )}{2}+\frac {a^2\,c\,d\,\left (d+c\,1{}\mathrm {i}\right )\,3{}\mathrm {i}}{2}\right )}{f}+\frac {\ln \left (\mathrm {tan}\left (e+f\,x\right )+1{}\mathrm {i}\right )\,\left (a^2\,c^3\,2{}\mathrm {i}+6\,a^2\,c^2\,d-a^2\,c\,d^2\,6{}\mathrm {i}-2\,a^2\,d^3\right )}{f}-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (a^2\,d^3\,1{}\mathrm {i}+a^2\,d^2\,\left (d+c\,3{}\mathrm {i}\right )\,1{}\mathrm {i}-a^2\,c^2\,\left (3\,d+c\,1{}\mathrm {i}\right )\,1{}\mathrm {i}-3\,a^2\,c\,d\,\left (d+c\,1{}\mathrm {i}\right )\right )}{f}+\frac {{\mathrm {tan}\left (e+f\,x\right )}^3\,\left (\frac {a^2\,d^3\,1{}\mathrm {i}}{3}+\frac {a^2\,d^2\,\left (d+c\,3{}\mathrm {i}\right )\,1{}\mathrm {i}}{3}\right )}{f}-\frac {a^2\,d^3\,{\mathrm {tan}\left (e+f\,x\right )}^4}{4\,f} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 1.35, size = 389, normalized size = 2.76 \[ - \frac {2 i a^{2} \left (c - i d\right )^{3} \log {\left (e^{2 i f x} + e^{- 2 i e} \right )}}{f} + \frac {6 a^{2} c^{3} - 36 i a^{2} c^{2} d - 42 a^{2} c d^{2} + 16 i a^{2} d^{3} + \left (18 a^{2} c^{3} e^{2 i e} - 126 i a^{2} c^{2} d e^{2 i e} - 150 a^{2} c d^{2} e^{2 i e} + 58 i a^{2} d^{3} e^{2 i e}\right ) e^{2 i f x} + \left (18 a^{2} c^{3} e^{4 i e} - 144 i a^{2} c^{2} d e^{4 i e} - 198 a^{2} c d^{2} e^{4 i e} + 72 i a^{2} d^{3} e^{4 i e}\right ) e^{4 i f x} + \left (6 a^{2} c^{3} e^{6 i e} - 54 i a^{2} c^{2} d e^{6 i e} - 90 a^{2} c d^{2} e^{6 i e} + 42 i a^{2} d^{3} e^{6 i e}\right ) e^{6 i f x}}{3 i f e^{8 i e} e^{8 i f x} + 12 i f e^{6 i e} e^{6 i f x} + 18 i f e^{4 i e} e^{4 i f x} + 12 i f e^{2 i e} e^{2 i f x} + 3 i f} \]
Verification of antiderivative is not currently implemented for this CAS.
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